Chemistry | Mechanical Engineering | TANCET Anna University Online Objective Test

TANCET Anna University Mechanical Engineering # Chemistry Redox Reactions Prepare / Learn

Q1. The oxidizing power of halogens increase in the order of

A. F2<I2<Br2<Cl2

B. Cl2<F2< I2< Br2

C. II2<Br2<Cl2<F2

D. Br2<Cl2<F2< I2

Answer : Option C
Explaination / Solution:

Halogens have high electronegativity and electron affinity. They have greater tendency to accept electrons or easily reduced, therefore they are strong oxidizing agent. As the reduction potential decrease down the group,the oxidizing power decrease down the group the order of the oxidizing power will be as under F2 > Cl2> Br2> I2 ¥ The oxidizing power depends on, Heat of dissociation of halogen molecule. Electron affinity of atom. Hydration energy of the ion. Heat of vaporization If a halogen has low energy of dissociation, a high electron affinity, and higher hydration of its ion, it will have high oxidizing power. F has although low electron affinity than Cl but low dissociation energy and have high hydration energy of its ion, therefore Fluorine is strongest oxidizing agent.

TANCET Anna University Mechanical Engineering # Chemistry Organic compounds containing Nitrogen Prepare / Learn

Q2. Aniline does not undergo one of the following

A. Bromination

B. Sulphonation

C. alkylation and acetylation

D. Nitration

Answer : Option C
Explaination / Solution:

Because of lot of electron density on N of

N H 2.

TANCET Anna University Mechanical Engineering # Chemistry Some Basic Concepts of Chemistry Prepare / Learn

Q3. How many molecules of H2O are there in 18g of water?(Hint: Avagadro’s Number = 6.02 x 1023 atoms/mol)

A. 6.022 x 1024

B. 8.02 x 1023

C. 7.02 x 1023

D. 6.022 x 1023

Answer : Option D
Explaination / Solution:

Since , the number of molecules contained in one mole of a substance = Avogadro's number (N) = 6.022 x 1023 molecules ,and , gram molar mass of water= 18 g

∴

18g H2O = 1mol water

$∴$ one mol of water would contain

= 6.022 x 1023 molecules of water

TANCET Anna University Mechanical Engineering # Chemistry Equilibrium Prepare / Learn

Q4.

B F_{3}

does not have proton but still acts as an acid and reacts with NH3. Why is it so? What type of bond is formed between the two?

B F_{3}

is a Lewis acid and coordinate bond is formed

B F_{3}

is a Lewis acid and coordinate bond is formed

B F_{3}

is a Brönsted acid and coordinate bond is formed

B F_{3}

is a Brönsted acid and coordinate bond is formed

Answer : Option B
Explaination / Solution:

B F_{3}

is a Lewis acid as B has its vacant p orbital and coordinate bond is formed as

N H_{3}

donates its lp of electrons to the vacant orbital of B.

TANCET Anna University Mechanical Engineering # Chemistry Hydrocarbons Prepare / Learn

Q5. Which one of these is NOT TRUE for benzene? Explanation: Benzene forms mono substituted product.

A. Heat of hydrogenation of benzene is less than the theoretical value

B. The bond angle between carbon-carbon bonds is

12 0^{\circ}

There are three carbon-carbon single bonds and three carbon-carbon double bonds

It forms only one type of monosubstituted product

Answer : Option C
Explaination / Solution:
No Explaination.

TANCET Anna University Mechanical Engineering # Chemistry General Principles and Processes of Isolation of Elements Prepare / Learn

Q6. Refining of silver is done by

A. Cupellation

B. Zone refining

C. Poling

D. Liquation

Answer : Option A
Explaination / Solution:

Ag is refined by Cupellation.

TANCET Anna University Mechanical Engineering # Chemistry The p-Block Elements Prepare / Learn

Q7. Xenondifluoride is

A. Pyramidal

B. Linear

C. Angular

D. Trigonal

Answer : Option B
Explaination / Solution:

CN=0.5(V+M-C+A) For XeF_2 CN = 5 so shape will be linear and structure will be trigonal pyramidal.

TANCET Anna University Mechanical Engineering # Chemistry Solid State Prepare / Learn

Q8. In cubic close packing(ccp) arrangement, the pattern of the successive layers will be designated as

A. ABC, ABC,ABC

B. AB, ABC,AB, ABC….

C. none of the above

D. AB,AB,AB….

Answer : Option A
Explaination / Solution:

Ist layer and 4th layer are same.

TANCET Anna University Mechanical Engineering # Chemistry Polymers Prepare / Learn

Q9. Copolymerisation of 1, 3 – butadiene and acrylonitrile needs

A. peroxide catalyst

B. antimony trioxide catalyst

C. zinc acetate catalyst

D. persulphate catalyst

Answer : Option A
Explaination / Solution:

Copolymerisation of 1,3-butadiene and acrylonitrile requirw peroxide catalyst.

TANCET Anna University Mechanical Engineering # Chemistry Classification of Elements and Periodicity in Properties Prepare / Learn

Q10. The increasing order of bond dissociation energies of following species is -----?

A. Cl2< O2< N2< F2

B. N2< O2< F2< Cl2

C. F2< Cl2< O2< N22

D. F2< N2< Cl2< O2

Answer : Option C
Explaination / Solution:

As bond order increases bond dissociation energy also increases .

Thus $N_{2}$

(i) the triple bonded $N_{2}$ with bond order

= 3

has the highest bond dissociation energy .

(ii) The doubly bonded $O_{2}$ with bond order

= 2

has lesser bond dissociation energy than $N_{2}$

(iii) $F_{2}$ and $C l_{2}$ both are single bonded having the same bond order

= 1

but , the electron - electron repulsive force ( e - e repulsion ) is maximum in a $F_{2}$ molecule due to its small size. This accounts for the lower bond dissociation energy of $F_{2}$ as compared to $C l_{2}$

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