w = – P ∆ V
w = – (1 × 105 Nm–2)
(1× 10–2 m3 – 1 × 10–3
m3)
w= –105 (10–2 – 10–3)
Nm
w = – 105 (10 – 1) 10–3) J
w = – 105 (9 × 10–3) J
w = –9 × 102 J w = –900 J
CO (g )+1/2O2 (g )→CO 2
(g)
ΔHC0 (CO) = ΔHf (CO2)
– ΔHf(CO) + ΔHf (O2)]
ΔHC0 (CO) = ΔHf (CO2)
– ΔHf(CO) + ΔHf (O2)]
ΔHC0 (CO) = –
94 KCal – [– 26.4 KCal + 0]
ΔHC0 (CO) = –
94 KCal + 26.4
KCal ΔHC0 (CO) = –
67.4 Kcal