2 R - OH + 2Na→ 2 RONa + H2↑2 moles of alcohol gives 1 mole of H2
which occupies 22.4L at 273K and 1 atm
∴ number of moles of alcohol = ( 2
moles of R - OH / 22.4 L of H2 ) × 560 mL
= 0.05 moles
∴ no. of moles = mass / molar mass
⇒ molar mass = 3.7/0.05 = 74 g mol−1
General
formula for R - OH Cn H2n+1 - OH
∴ n(12) + (2n+1) (1) + 16+1=74
14n = 74 – 18
14n = 56
∴ n = 56/14 = 4
The 2 alcohol which contains 4
carbon is CH2 CH(OH)CH2CH3