Q1.Which among the following statement is not true for catalyst?
Answer : Option CExplaination / Solution:
Catalyst does not change the equilibrium constant it only helps in reaching the equilibrium at a faster rate,i.e. it catalyses the forward as well as teh backward reactions to the same extent so that the equilibrium state remains same but is reached earlier.
Q3.Above the Critical temperature (TC) of carbon dioxide
Answer : Option DExplaination / Solution:
Tc is the highest Temp where a gas can exist in liquid state. Above this no liquid state exist hence it is not possible to liquify the gas no matter what pressure is applied.
Q4.A catalyst increases the rate of the chemical reaction for the conversion of reactants to products by
Answer : Option CExplaination / Solution:
A catalyst increases the rate of the chemical reaction by making available a new low energy pathway for the conversion of reactants to products. It increases the rate of forward and reverse reactions that pass through the same transition state and does not affect equilibrium. Catalyst lowers the activation energy for the forward and reverse reactions by exactly the same amount. Catalyst does not affect the equilibrium composition of a reaction mixture. It does not appear in the balanced chemical equation or in the equilibrium constant expression.
Q6.One of the following alcohols do not undergo oxidation reaction
Answer : Option AExplaination / Solution:
The outcome of oxidation reactions of alcohols depends on the
substituents on the carbinol carbon. In order for each oxidation step to
occur, there must be H on the carbinol carbon.
Primary alcohols can be oxidised to aldehydes or further to
carboxylic acids. In aqueous media, the carboxylic acid is usually the
major product. PCC or PDC, which are used in dichloromethane, allow the
oxidation to be stopped at the intermediate aldehyde.
Secondary alcohols can be oxidised to ketones but no further:
Tertiary alcohols cannot be oxidised (no carbinol C-H)
Q7.The unusual behavior of benzene is explained by
Answer : Option DExplaination / Solution:
resonance stabilisation explains the unusual stability of benzene.There is pi electron delocalisation in the ring which enhances the stability of the molecule.
Q10.In oxygen difluoride (OF2) and dioxygen difluoride(O2F2), the oxygen is assigned an oxidation number of
Answer : Option AExplaination / Solution: Oxidation state of O in OF2 is +2 and O2F2 is +1. Because the number assigned to oxygen will depend upon the bonding state of oxygen.
Total Question/Mark :
Scored Mark :
Mark for Correct Answer : 1
Mark for Wrong Answer : -0.5
Mark for Left Answer : 0