Ca(OH)2 ↔ Ca2+
+ 2OH-
Given that pH = 9
pOH = 14-9 = 5
[pOH = -log10 [OH- ]]
∴[OH- ] = 10- pOH
[OH- ]=10-5
M
Ksp =[Ca2+
][OH- ]2
= (10-5 /2 )×(10-5 )2
=0.5 ×10-15
Λ = κ/M ×10−3 mol−1 m3
= [( 5.76 × 10−3 S cm−1 ×10−3 ) / (0. 5)]
mol−1m3
= [(5.76 × 10−3 × 10−3 ×106 ) / (0.5)] S cm−1mol−1 cm3 .
= 11.52 S cm2 mol−1
Assertion : Coagulation power of Al3+ is more than Na+
.
X-HCHO
Y-(CH2 )6N4