General Science - Online Test
Q1. Building unit of protein is.
Answer : Option A
Explaination / Solution:
Protein is built by α – Aminoacid
Q2. What are most of the Earth's deserts characterized by?
Answer : Option D
Explaination / Solution:
No Explaination.
Q3. Full form of ICBN is
Answer : Option B
Explaination / Solution:
ICBN stands for International code of botanical nomenclature that frames rules for nomenclature of plants applicable for all over the world.
Q4. Vascular bundles in which cambium is present between xylem and phloem is called as
Answer : Option A
Explaination / Solution:
Vascular bundles in which cambium is present between xylem and phloem is called open vascular bundles and those in which cambium is absent is called closed vascular bundles.
Q5. Phytochrome is sensitive to
Answer : Option C
Explaination / Solution:
Phytochrome is a photoreceptor and a pigment that plants, and some bacteria and fungi, use to detect light. It is sensitive to light in the red and far-red region of the visible spectrum.
Q6.
Calculate the molarity of liquid HCl solution whose density is 1.17 g/cm3
.
Answer : Option C
Explaination / Solution:
M= (1.17 x 1000)(36.5)
Q7. Following are the external factors responsible for industrial sickness except
Answer : Option A
Explaination / Solution:
Diversion of funds is the internal cause and not the external cause for industrial sickness.
Q8. Sparrow is
Answer : Option B
Explaination / Solution:
Sparrow feeds on fruits as well insects. Herbivores or plant eaters are primary consumer and carnivores that feed on herbivores are secondary consumer. So, Sparrow occupy both primary and secondary trophic levels.
Q9. Capital expenditure is incurred on normal functioning of the govt. Administration. It is
Answer : Option C
Explaination / Solution:
No Explaination.
Q10. The mean of ten numbers is 58. If one of the numbers is 40, what is the mean of the other nine?
Answer : Option B
Explaination / Solution:
Mean is calculated as the sum of the values of all observations divided by the number of observations
Mean = 58, N= 10
sum of the values of all observations = 58 x 10 = 580
Corrected sum of the values of all observations = 580 - 40 = 540
Corrected number of observations = 10 – 1 = 9
Correct Mean = 540/9 = 60
Mean = 58, N= 10
sum of the values of all observations = 58 x 10 = 580
Corrected sum of the values of all observations = 580 - 40 = 540
Corrected number of observations = 10 – 1 = 9
Correct Mean = 540/9 = 60
