
Mass of the man, m = 70 kg
Acceleration, a = 0
UsingNewton’s second law of motion,
wecan write the equation of motion as:
R – mg = ma
Where, ma is the net force acting on the man.
As the lift is moving at a uniform speed, acceleration a = 0
∴ R = mg = 70 × 10 = 700 N
∴ Reading on the weighing scale = 700 / g = 700 / 10 = 70 kg

Since , Molarity
=
substituting the given values , we get -
Molarity ( M )
=
=0.4M
* moles of solute ie. NaOH = mole
.= 0.1mol