General Science - Online Test

Q1. In a hierarchical system of classification of plants, which of the following taxonomic rank ends in ‘ceae’?
Answer : Option A
Explaination / Solution:

Plant families like Convolvulaceae, Solanaceae are included in the order Polymoniales mainly based on the floral characters. Hence, the correct option is Family.

Q2. Growth regulator ethylene is used for
Answer : Option C
Explaination / Solution:

Ethylene is highly effective in fruit ripening. It enhances the respiration rate during ripening of the fruits.

Q3. In pressure cooker boiling point of water
Answer : Option A
Explaination / Solution:

As pressure increases boiling point also increase.

Q4. Life expectancy in 1991 was
Answer : Option C
Explaination / Solution:

Life expectancy refers to the the average period that a person may expect to live. In 1991 life expectancy was between 60 and 61 years.

Q5. What is common between vegetative propagation and apomixes
Answer : Option B
Explaination / Solution:

Both vegetative propagation and apomixes are types of asexually reproduction involving not fusion of gametes. So, new progeny produced are identical to parents.

Q6. Examples of local and global nutrient cycles will be:
Answer : Option B
Explaination / Solution:

Phosphorus cycle occurs at local level in an ecosystem as it is mainly derived from soil. Carbon cycles occurs through environment and affected by different ecosystem present on earth surface. So, carbon cycle is global in nature.

Q7. Public expenditure can be planned only
Answer : Option C
Explaination / Solution:
No Explaination.


Q8. According to the text, which of the following represents the highest peak of the distribution?
Answer : Option C
Explaination / Solution:

The mode is the most frequent score in our data set. It represents the highest peak of the distribution.

Q9. Disguised unemployment is
Answer : Option A
Explaination / Solution:

More workers employed on a single piece of work than actually required is called as the disguised unemployment.

Q10.

A truck starts from rest and accelerates uniformly at 2.0 m . At t = 10 s, a stone is dropped by a person standing on the top of the truck (6 m high from the ground). What is the magnitude of acceleration (in m  ) of the stone at t = 11s? (Neglect air resistance.)


Answer : Option D
Explaination / Solution:

When the stone is dropped from the truck , the horizontal force acting on it become zero after stone is released. Stone continue to move under the influence of gravity only. So that acceleration of the stone is equal to the gravitational acceleration g.

a = g = 10ms-2 acting vertically downward.