Mathematics - Online Test
Q1. The coefficient of second, third and fourth terms in the binomial expansion of ( ‘n’, a + ve integer) are in A.P.., if n is equal to
Answer : Option B
Explaination / Solution:
Q2. If n (A ) =3 and n ( B ) = 6 and A⊆ B , then n(A∪B)=?
Answer : Option B
Explaination / Solution:
Q3.
The tangent to the parabola at the point makes with the X – axis an angle of
Answer : Option D
Explaination / Solution:
Therefore , slope of tangent at ( 1 , ½ ) = 1. Hence , required angle is
Therefore , slope of tangent at ( 1 , ½ ) = 1. Hence , required angle is
Q4.
The area bounded by the ellipse and the straight line x + 3y = 3 is
Answer : Option A
Explaination / Solution:
Q5. The solution set for : 3x − 7 >x + 3.
Answer : Option D
Explaination / Solution:
Q6. is equal to
Answer : Option B
Explaination / Solution:
Q7. Maximize Z = 3x + 2y subject to x + 2y ≤ 10, 3x + y ≤ 15, x, y ≥ 0.
Answer : Option A
Explaination / Solution:
Objective function is Z = 3x + 2 y ……………………(1).
The given constraints are : x + 2y ≤ 10, 3x + y ≤ 15, x, y ≥ 0. The corner points obtained by drawing the lines 3x+y=15 and x+2y=10 graphically are (0,0),(0,5), (5,0) and (4,3).
Corner points | Z = 3x + 2y |
O(0 ,0 ) | 0 |
A(5,0) | 15 |
B(0,5) | 10 |
C(4,3) | 18……………………..(Max.) |
Here , Z = 18 is maximum at ( 4, 3 )
Q8. The values of ‘a’ for which the roots of the equation sin θ = a in A.P. are
Answer : Option A
Explaination / Solution:
Q9. If in moderately asymmetrical distribution mode and mean of the data are 6 μ and 9 μ respectively, then median is
Answer : Option A
Explaination / Solution:
median=mode+2mean3=6μ+2(9μ)3=24μ3=8μ
Q10.
R is a relation from { 11, 12, 13} to {8, 10, 12} defined by y = x – 3. The relation =
Answer : Option B
Explaination / Solution:
R is a relation from { 11, 12, 13} to {8, 10, 12} defined by y = x – 3. The relationis given by x = y + 3,from {8, 10, 12} to { 11, 12, 13} relation = {(8,11),(10,13)}.
