Find the equation of the line which passes through the point (1, 2, 3) and is parallel to the vector3i^+2j^−2k^.
Answer : Option DExplaination / Solution: The equation of the line which passes through the point (1, 2, 3) and is parallel to the vector 3i^+2j^−2k^ , let vector a→=iˆ+jˆ+kˆ and vector b→=3i^+2j^−2k^, the equation of line is : a→+λb→=(iˆ+jˆ+kˆ)+λ(3i^+2j^−2k^).
Q10.Angles of triangle are in A.P. If the number of degrees in the smallest to the number of radians in the largest is as 60:π, then the smallest angle is
Answer : Option AExplaination / Solution:
Total Question/Mark :
Scored Mark :
Mark for Correct Answer : 1
Mark for Wrong Answer : -0.5
Mark for Left Answer : 0