Mathematics - Online Test
Q1. The general solution of the equation cotθ−tanθ=secθis(n∈I)
Answer : Option B
Explaination / Solution:
Q2. is
Answer : Option B
Explaination / Solution:
there fore answer is negative
there fore answer is negative
Q3. The statement is true for all
Answer : Option C
Explaination / Solution:
Since if n = 1 we have 3>4, which is not true . If n = 2 then 9>8, which is true.
Q4. The function, f (x) = (x – a) sin for x a and f (a) = 0 is
Answer : Option D
Explaination / Solution:
Q5. Which one of the following lines is farthest from the centre of the circle
Answer : Option D
Explaination / Solution:
after completing the square,we get
so center is (0,0) and equation of given line is 
by applying formula of distance of a point from a given line i.e., 
where(x1,y1) are the coordinates of point and A and B are coefficient of x,y in given line so d =
which is greatest.
by applying formula of distance of a point from a given line i.e., where(x1,y1) are the coordinates of point and A and B are coefficient of x,y in given line so d =
Q6. Function y = f(x) is said to satisfy a differential equation g (y, y’, y’’...) =h(x) if
Answer : Option C
Explaination / Solution:
Function y = f(x) is said to satisfy a differential equation g (y, y’, y’’...) =h(x) if y and its derivatives substituted in equation g (y, y’, y’’...) =h(x) yield L.H.S. = R.H.S.
Q7.
If is the acute angle between , then
Answer : Option C
Explaination / Solution:
If is the acute angle between , then cosine of the angle between these two lines is given by : 
Q8. In a ΔABCΔABC , if a sin A = b sin B then the triangle is
Answer : Option C
Explaination / Solution:
Hence the triangle is isosceles.
Q9. The letters of the word ‘SOCIETY’ are arranged in such a manner that the vowels and consonants occur alternately, the number of different words so obtained is
Answer : Option B
Explaination / Solution:
there are four consonants and 3 vowels, therefore 3! * 4!
Q10. The area of the curve is
Answer : Option C
Explaination / Solution:
Given equation is of a circle ; Its radius is equal to a. Therefore required area is =
