Mathematics - Online Test
Area of the triangle formed by the coordiates( x1,y1), (x2,y2) and (x3,y3) is given by
[x1(y2 - y3) + x2(y3 - y1) + x3(y1 - y2)]
On solving the lines 1 and 2, the point of intersection is (0,0)
On solving the lines 2 and 3, the point of intersection is (4,8)
\On solving the line 3 and 1 , the point of intersection is (-2,-2)
Now substituting the values to find the area of the triangle,
Area = | [ 0 + 4(-2-0) +(-2)(0 - 8)] |
= 4 sq units
Find the values of x and y so that the vectors are equal
Solving the above two equations we get,
---(i)
---(ii)
Squaring both sides of (i) and (ii) and adding both the equation we get x2+y2=a2+b2.
which represents the locus of circle as
(i) it is quadratic equation
(ii) coeff of x2 = coeff of y2
(iiI) there is no trerm involving xy.
