Mathematics - Online Test
Q1. Area bounded by the curves satisfying the conditions is given by
Answer : Option A
Explaination / Solution:
Q2. Solve the inequality 3 − 2x ≤ 9
Answer : Option D
Explaination / Solution:
Q3. Ltx→01x
Answer : Option A
Explaination / Solution:
Q4. In a LPP if the objective function Z = ax + by has the same maximum value on two corner points of the feasible region, then every point on the line segment joining these two points give the same
Answer : Option C
Explaination / Solution:
In a LPP if the objective function Z = ax + by has the same maximum value on two corner points of the feasible region, then every point on the line segment joining these two points give the same maximum value . If the problem has multiple optimal soliutions at the corner points, then both the points will have the same (maximum or minimum)value.
Q5. Sum of first 5 terms of an A.P. is one fourth of the sum of next five terms. If the first term = 2, then the common difference of the A.P. is
Answer : Option D
Explaination / Solution:
Q6. The mean weight of a group of 10 items is 28 and that of another group of n items is 35.The mean of combined group of 10 + n items is found to be 30. The value of n is
Answer : Option A
Explaination / Solution:
sum of weights of 10 items =280
sum of weights of n items = 35n
so, sum of weights of ( 10 + n) items = 280 + 35n
so ,mean = (280 + 35 n) / ( 10 + n)
30(10 + n ) = 280 + 35n
solving we get, n = 4
Q7. Which one of the following statements is true for all real symmetric matrices?
Answer : Option A
Explaination / Solution:
Eigen values of a real symmetric matrix are all real
Q8. The void relation ( a subset of A x A ) on a non empty set A is :
Answer : Option C
Explaination / Solution:
The relation { }⊂ A x A on a is surely not reflexive.However ,neither symmetry nor transitivity is contradicted .So { } is a transitive and symmetric relation on A.
Q9. 
Answer : Option D
Explaination / Solution:
Q10.
Let f (x) – log(1 + x), where x > 0, then f is
Answer : Option C
Explaination / Solution:
Hence decreasing function.
