Q1.The old city of Koenigsberg, which had a German majority population before World War 2, is now called Kaliningrad. After the events of the war, Kaliningrad is now a Russian territory and has a predominantly Russian population. It is bordered by the Baltic Sea on the north and the countries of Poland to the south and west and Lithuania to the east respectively. Which of the statements below can be inferred from this passage?
Answer : Option BExplaination / Solution:
Ethnic cleansing or makeup is the process of using violent methods to force
certain groups of people out of a particular area or country. We can infer that
Kaliningrad was historically Russian in its ethnic make up.
Q2.The number of people diagnosed with dengue fever (contracted from the bite of a mosquito) in north India is twice the number diagnosed last year. Municipal authorities have concluded that measures to control the mosquito population have failed in this region.
Which one of the following statements, if true, does not contradict this conclusion?
Answer : Option DExplaination / Solution: No Explaination.
Q4.The magnitude of magnetic flux density at a point having normal distance d meters from
an infinitely extended wire carrying current of l A is (in SI units). An infinitely
extended wire is laid along the x-axis and is carrying current of 4 A in the +ve x direction.
Another infinitely extended wire is laid along the y-axis and is carrying 2 A current in the +ve
y direction µ0 is permeability of free space Assume to be unit vectors along x, y and
z axes respectively.
Assuming right handed coordinate system, magnetic field intensity, at coordinate (2,1,0)
Q7.Which of the following is an invalid state in an 8-4-2-1. Binary Coded Decimal counter
Answer : Option DExplaination / Solution:
In binary coded decimal (BCD) counter the valid states are from 0 to 9 only in binary system 0000 to 1001 only. So, 1100 in decimal it is 12 which is invalid state in BCD counter.
Q8.A 10 kHz even-symmetric square wave is passed through a bandpass filter with centre frequency at 30 kHz and 3 dB passband of 6 kHz. The filter output is
Answer : Option CExplaination / Solution:
10 KHz even symmetric square wave have frequency component present 10KHz, 30KHz, 50KHz, 70KHz
[only odd harmonics due to half wave symmetry]
Since bandpass filter is contered at 30KHz, 30KHz component will pass through
filter output is nearly perfect cosine wave at 10 KHz
Cosine in due to reason that signal in even signal.