UNIT 9: Electro Chemistry - Online Test

Q1. Which of the following electrolytic solution has the least specific conductance
Answer : Option B
Explaination / Solution:

In general, specific conductance of an electrolyte decreases with dilution. So, 0.002N solution has least specific conductance.

Q2. While charging lead storage battery
Answer : Option C
Explaination / Solution:

Charging : anode : PbSO4 (s)+ 2e Pb (s) + SO4-2 (aq)

Cathode : PbSO4 (s)+ 2H2 O (l) PbO2 (s) + SO4-2 (aq)+2e


Q3.

Among the following cells

I) Leclanche cell

II) Nickel – Cadmium cell

III) Lead storage battery

IV) Mercury cell

Primary cells are
Answer : Option A
Explaination / Solution:
No Explaination.


Q4. Zinc can be coated on iron to produce galvanized iron but the reverse is not possible. It is because
Answer : Option D
Explaination / Solution:

EoZn2+|Zn = − 0.76V and EoFe2+|Fe = −0.44V Zinc has higher negative electrode potential than iron, iron cannot be coated on zinc.


Q5.

Assertion : pure iron when heated in dry air is converted with a layer of rust.

Reason : Rust has the composition Fe3 O4
Answer : Option D
Explaination / Solution:

Both are false

i) Dry air has no reaction with iron

ii) Rust has the composition Fe2 O3 . x H2


Q6. In H2 -O2 fuel cell the reaction occurs at cathode is
Answer : Option A
Explaination / Solution:
No Explaination.


Q7.

17. The equivalent conductance of M/36 solution of a weak monobasic acid is 6 mho cm2 equivalent –1 and at infinite dilution is 400 mho cm2 equivalent –1. The dissociation constant of this acid is

Answer : Option B
Explaination / Solution:

 α = Λ / Λo = 6/400

Ka2C

= 6/400 × 6/400 × 1/36

= 6.25 ×10−6


Q8. A conductivity cell has been calibrated with a 0.01M, 1:1 electrolytic solution (specific conductance ( κ =1.25 ×103 S cm1 ) in the cell and the measured resistance was 800 W at 25º C . The cell constant is,
Answer : Option C
Explaination / Solution:

R = ρ. l/A

cell constant = R/ρ

= κ.R       (1/ ρ =κ )

= 1.25 × 10−3 Ω−1cm−1 × 800 Ω

= 1 cm−1


Q9. Conductivity of a saturated solution of a sparingly soluble salt AB (1:1 electrolyte) at 298K is 1 .85 ×105 S m1 . Solubility product of the salt AB at 298K ( Λºm )AB = 14 × 103 S m2 mol1 .
Answer : Option D
Explaination / Solution:
No Explaination.


Q10. In the electrochemical cell: Zn | ZnSO4 (0.01M) || CuSO4 (1.0M) | Cu , the emf of this Daniel cell is E1. When the concentration of is changed to 1.0M and that CuSO4 changed to 0.01M, the emf changes to E2. From the above, which one is the relationship between E1 and E2?
Answer : Option B
Explaination / Solution:

Zn(s) → Zn2+ (aq) + 2e-

Cu2+ (aq)+2e- → Cu(s)

Zn(s) +Cu2+ (aq) → Zn2+ (aq) + Cu(s)

Ecell =Eºcell – (0.0591/2) log ( [zn2+]/ [Cu2+] )

E1 =Eºcell - 0.0591/2 log (10-2/1)

E1 =Eocell + 0.0591 ........(1)

E2 =Eºcell - 0.0591/2 log (1/10-2)

E2 =Eocell - 0.0591 .........(2)

E1>E2