Consider the change in oxidation state of Bromine corresponding to
different emf values as shown in the diagram below:
Then the species undergoing disproportionation is
( Ecell )A =-1.82+1.5=-0.32V
( Ecell )B =-1.5+1.595=+0.095V
( Ecell )c =-1.595+1.0652=-0.529V
The species undergoing
disproportionation is HBrO
For the cell reaction
2Fe3+ (aq) + 2l−(aq) → 2Fe2+ (aq) + l2 (aq)
Cell equation : A + 2B- → A2+
+2B;