Givena+b+c=6(sinA+sinB+sinC)3⇒a+b+c=2(sinA+sinB+sinC)Nowusingsinerulea=ksinA,b=ksinB,c=ksinC⇒k(sinA+sinB+sinC)=2(sinA+sinB+sinC)⇒k=2
Now when
A square matrix A for whichAn= 0, where n is a positive integer, is called a Nilpotent matrix.
The determinant and trace of the matrix is always Zero for a Nilpotent Matrix.
For the given matrix "A", determinant (A)=0 and trace(A)=0.