Mathematics - Online Test

Q1. A coin tail on both sides is tossed twice. The probability of getting ‘a head’ is
Answer : Option D
Explaination / Solution:
No Explaination.


Q2. A condition for a function y = f (x) to have an inverse is that it should be
Answer : Option B
Explaination / Solution:
No Explaination.


Q3. The chance that an event E ‘occurs’ or does not occur’s
Answer : Option A
Explaination / Solution:
No Explaination.


Q4. Set A has 3 elements and set B has 4 elements. The number of injections that can be defined from A to B is
Answer : Option D
Explaination / Solution:
No Explaination.


Q5. Mean number of ‘sixes’ in four throws of a fair dic is
Answer : Option C
Explaination / Solution:
No Explaination.


Q6.
The range of the function  is

Answer : Option B
Explaination / Solution:
No Explaination.


Q7. From a deck of 52 cards, the probability of drawing a court card is
Answer : Option B
Explaination / Solution:
No Explaination.


Q8.
On the set Z of all integers define f ; Z  Z as follows : f ( x ) = x/2 if x is even , and f ( x ) = 0 if x is odd , then f is

Answer : Option D
Explaination / Solution:
No Explaination.


Q9. Two players toss four coins each. The probability that both obtain the same number of heads is
Answer : Option D
Explaination / Solution:

Let X denote same number of heads Both will get.

So X can take values 

X=0 ( both get 0 number of head)

X =1 ( both get 1 head)

X = 2 ( both get 2 heads)

X = 3 ( both get 3 heads)

X = 4 ( both get 4 heads)

So , P(X = 0 ) =Probabilty of getting no heads= 1/16 × 1/16 = 1/256      [by multiplication theorem  P(Xi Xj) = P(Xi).P(Xj) ]

P(X=1) =  Probabilty of getting 1 head = 4/16 × 4/16 = 16/256

P(X =2) = Probabilty of getting 2 heads =  6/16 × 6/16 = 36/256

P ( X = 3) =Probabilty of getting 3 heads=4/16 × 4/16 = 16/256

P( X= 4) =Probabilty of getting 4 heads = 1/16 × 1/16 = 1/256

Therefore P ( both get same number of head in a throw of 4 coins each )

= P(X=0) + P(X=1) + P(X=2) + P(X =3) + P(X =4)

= 1/256 + 16/256 + 36/256 + 16/256 + 1/256

= 70/256 = 35/128


Q10.
Let f : R R be defined by f (x) = 3x – 4, then  (x) is equal to

Answer : Option B
Explaination / Solution:
No Explaination.