Mathematics - Online Test

Q1. The diagram given below shows that

Answer : Option A
Explaination / Solution:

Because , an object in domain cann’t have two images in its co-domain.

Q2. Find the area of triangle with vertices ( 0 ,0 ),(4 , 2) and ( 1,1).
Answer : Option D
Explaination / Solution:



Q3. Three points A , B and C are collinear if the area of triangle ABC is
Answer : Option D
Explaination / Solution:

Only non collinear points can form a triangle. Hence if the three points are collinear a triangle cannot be formed, hence the area of the triangle is zero

Q4. Let p and q be two propositions. Then the contrapositive of the implication p→q is
Answer : Option A
Explaination / Solution:

The contrapositive of p→q≡∼q→∼p

Q5. The area bounded by the curve y = 2x -  and the line x + y = 0 is
Answer : Option D
Explaination / Solution:

The equation y =  i.e.represents a downward parabola with vertex at ( 1, 1 ) which meets x – axis where y = 0 .i .e . where x = 0 , 2. Also , the line y = - x meets this parabola where – x =  i.e. where x = 0 , 3.
Therefore , required area is :


Q6. If θ is the angle between vectors   then the cross product 
Answer : Option D
Explaination / Solution:

If  is the angle between vectors  then, the cross product : 
 .

Q7. ∫ |x| dx
Answer : Option C
Explaination / Solution:



Q8. is equal to
Answer : Option A
Explaination / Solution:




Q9. The locus of a variable point whose distance from the point ( 2, 0) is  times its distance from the line  is
Answer : Option A
Explaination / Solution:

Let the point be (x,y)

Hence (x-2)2 + (y-0)2 = 

(x- 2)2 + y2 = (x - 9/2)

On simplifying we get the equation of an ellipse


Q10. In a triangle ABC, if a, b, c are in A. P., then tan  are in
Answer : Option A
Explaination / Solution: