Electronic Science - Online Test

Q1. In the circuit shown below, the knee current of the ideal Zener dioide is 10 mA . To maintain 5 V across RL, the minimum value of RL in Ω and the minimum power rating of the Zener diode in mW, respectively, are

Answer : Option B
Explaination / Solution:
No Explaination.


Q2. If X = 1 in logic equation Then
Answer : Option D
Explaination / Solution:


Substituting X = 1 and we get
                                                                   1 + A = 1 and 0 + A = A

Q3. In the circuit shown, the power supplied by the voltage source is

Answer : Option A
Explaination / Solution:

Applying nodal analysis

Current from voltage source is

Since current through voltage source is zero, therefore power delivered is zero.

Q4. The small-signal resistance   in kW offered by the n-channel MOSFET M shown in the figure below, at a bias point of V= 2V is (device data for M: device transconductance parameter ,  threshold voltage VTN = 1V,  and neglect body effect and channel length modulation effects)

Answer : Option A
Explaination / Solution:
No Explaination.


Q5. What are the minimum number of 2- to -1 multiplexers required to generate a 2- input AND gate and a 2- input Ex-OR gate
Answer : Option A
Explaination / Solution:

The AND gate implementation by 2:1 mux is as follows


Q6.
In the interconnection of ideal sources shown in the figure, it is known that the 60 V source is absorbing power.

Which of the following can be the value of the current source I ?
Answer : Option A
Explaination / Solution:

Circuit is as shown below

Since 60 V source is absorbing power. So, in 60 V source current flows from + to - ve direction So,
I + I1 = 12
I = 12 - I1
I is always less then 12 A So, only option (A) satisfies this conditions.

Q7. The ac schematic of an NMOS common-source state is shown in the figure below, where part of the biasing circuits has been omitted for simplicity. For the n-channel MOSFET M, the transconductance  and body effect and channel length modulation effect are to be neglected. The lower cutoff frequency in HZ of the circuit is approximately at

Answer : Option A
Explaination / Solution:
No Explaination.


Q8. The Boolean expression  simplifies to
Answer : Option C
Explaination / Solution:

Given the Boolean expression

We simplify the expression as


Q9. If the transfer function of the following network is

Answer : Option C
Explaination / Solution:





Q10. In the given circuit, the values of V1 and V2 respectively are

Answer : Option A
Explaination / Solution:

By Nodal analysis