




If the battery has e.m.f E, resitance of the potentiometer is R and the internal resistance of the battery is r, then the current I flowing in the potentiometer wire is given by,
The potential difference V across the potentiometer
The potential gradient = ( potential drop across the potentiometer)/ length of the potentiometer wire)
= V/l
= 1.6/1
Potential gradient = 1.6 V/m
The emf of the cell

