Q1.The circuit below implements a filter between the input current ii and the
output voltage v0. Assume that the opamp is ideal. The filter implemented is a
Answer : Option DExplaination / Solution:
From diagram we can write
Q3.For a narrow base PNP BJT, the excess minority carrier concentration (ΔnE for emitter, ΔpBfor base. ΔnCfor collector) normalized to equilibrium minority carrier concentration (nE0for emitter, pB0 for base, nC0 for collector) in the quasi-neutral emitter, base and collector regions are shown below. Which one of the following biasing modes is the transistor operating in?
Answer : Option CExplaination / Solution:
As per the change carrier profile, base – to – emitter junction is reverse bias and base to collector junction is forward bias, so it works in Inverse active.
Q4.X = and Y = are two 5-bit binary numbers represented in two’s complement format. The sum of X and Y represented in two’s complement format using 6 bits is
Answer : Option CExplaination / Solution:
MSB of Y is 1, thus it is negative number and X is positive number
Q5.In series combination of capacitors, potential drops across the individual capacitors are equal to
Answer : Option AExplaination / Solution: When capacitors are connected in series, they have equal charge but the potential difference across them is given by V1=QC1;V2=QC2... and so on.Therefore V∝1C
Q6.A resistance and a coil are connected in series and supplied from a single phase, 100 V, 50 Hz ac
source as shown in the figure below. The rms values of plausible voltages across the resistance (VR)
and coil (VC) respectively, in volts, are
Q7.The wire of the potentiometer has resistance 4 ohms and length 1 m. It is connected to a cell of e.m.f. 2 volts and internal resistance 1 ohm. The p.d. across the potentiometer wire is:
Answer : Option BExplaination / Solution:
If the battery has an e.m.f E, the resitance of the potentiometer is R and internal resistance of the battery is r, then the current I flowing in the potentiometer wire is given as,
I=E(R+r)I=2(4+1)I=0.4A
The potential difference V across the potentiometer is
Q8.A magnetic needle lying parallel to a magnetic field requires W units of work to turn it, through 600. The torque needed to maintain the needle in this position will be
Answer : Option BExplaination / Solution: the work done to turn a needle through an angle θ is W=mBcosθThe torque needed to maintain τ=mBsinθ.τW=tanθ.τ=Wtanθ=Wtan60=3–√W
Q10.The number of valence electrons in a good conductor is generally
Answer : Option DExplaination / Solution:
The electron theory states that all matter is composed of atoms and the atoms are composed of smaller particles called protons, electrons, and neutrons. The electrons orbit the nucleus which contains the protons and neutrons. It is the valence electrons that we are most concerned with in electricity. These are the electrons which are easiest to break loose from their parent atom. Normally, conductors have three or less valence electrons; insulators have five or more valence electrons; and semiconductors usually have four valence electrons.
Total Question/Mark :
Scored Mark :
Mark for Correct Answer : 1
Mark for Wrong Answer : -0.5
Mark for Left Answer : 0