Electronic Science - Online Test
Q1.
For a N -point FET algorithm N = 2m which one of the following statements is TRUE ?
Answer : Option D
Explaination / Solution:
For an N-point FET algorithm butterfly operates on one pair of samples and involves two complex addition and one complex multiplication.
Q2. The potential barrier in the depletion layer is due to
Answer : Option D
Explaination / Solution:
When p-n junction is formed, the electrons from n-region diffuse through the junction into p-region provide positive ions in n-region similarly holes from p-region diffuse into n-region provide negative ions in p-region. Due to these ions, an electric field is set up across the junction from positive ions to negative ions. This electric field sets a potential barrier at the junction.
Q3. When a “CALL Addr” instruction is executed, the CPU carries out the following sequential operations internally:
Note:
(R) means content of register R
((R)) means content of memory location pointed to by R
PC means Program Counter
SP means Stack Pointer
Answer : Option D
Explaination / Solution:
No Explaination.
Q4. An SCR is considered to be a semi-controlled device because
Answer : Option C
Explaination / Solution:
No Explaination.
Q5. Suppose that resistors R1 and R2 are connected in parallel to give an equivalent resistor R. If
resistors R1 and R2 have tolerance of 1% each., the equivalent resistor R for resistors R1 =
300Ω and R2 = 200Ω will have tolerance of
Answer : Option B
Explaination / Solution:
Q6. 
In the following a stable multivibrator circuit, which properties of V0(t) depend on R2?
Answer : Option A
Explaination / Solution:
The R2 decide only the frequency.
Q7. A metal plate of thickness half the separation between the capacitor plates of capacitance C, is inserted between the plates. The new capacitance is
Answer : Option D
Explaination / Solution:
The capacitance C of a parallel plate capacitor is given by A metal plate of thickness d/2 when introduced between the plates reduces the distance between the plates to d/2. The effective capacitance becomes
Another explanation: The system can be considered to be three capacitors , , and connected in series.
K of a metal is infinity. . The equivalent capacitance
Another explanation: The system can be considered to be three capacitors , , and connected in series.
K of a metal is infinity. . The equivalent capacitance
Q8. A particle having charge 100 times that of an electron is revolving in a circular path of radius 0.8 m with one rotation per second. Magnetic field produced at the centre of the circular path is
Answer : Option C
Explaination / Solution:
A charge moving in a circular path is equivalent to a current Since the particle has charge 100 times e and it makes 1 revolution per second,q=100e and T=1s.
The magnetic field at the centre
The magnetic field at the centre
Q9. Three voltmeters, all having different resistances, are joined as shown. When some potential difference is applied across A and B, their readings are V1, V2 , V3 .
Answer : Option D
Explaination / Solution:
V3 and combination of V1 and V2 (V1 + V2) are connected in parallel so potential in V3 must be equal to potential in (V1 + V2)
the potential difference across AB = = +.
Q10.
A toroid wound with 60.0 turns/m of wire carries a current of 5.00 A. The torus is iron, which has a magnetic permeability of under the given conditions. H and B inside the iron are
Answer : Option B
Explaination / Solution:
No Explaination.
