
According to Henderson equation
pH = pKa + log ([salt]/[acid])
ie. - log [H+ ] = -
log Ka +log ([salt] / [acid])
-log[H+] = log ([salt]/ [acid]) ×
(1/Ka)
log (1/[H+]) = log ([salt]/ [acid]) × (1/Ka)
∴[H+] = Ka
{[acid] / [salt] }
Consider the change in oxidation state of Bromine corresponding to
different emf values as shown in the diagram below:

Then the species undergoing disproportionation is

( Ecell )A =-1.82+1.5=-0.32V
( Ecell )B =-1.5+1.595=+0.095V
( Ecell )c =-1.595+1.0652=-0.529V
The species undergoing
disproportionation is HBrO
For the cell reaction
2Fe3+ (aq) + 2l−(aq) → 2Fe2+ (aq) + l2 (aq)
Assertion : Ce4+ is used as an oxidizing agent in
volumetric analysis.
