an2/V2 = atm
= atm L2/mol2 = L2
mol-2 atm
nb = L
b= L/mol = L mol-1
Match the equilibria with the corresponding conditions,
i) Liquid ⇌ Vapour
ii) Solid ⇌ Liquid
iii) Solid ⇌ Vapour
iv) Solute (s) ⇌ Solute
(Solution)
1. melting point
2. Saturated solution
3. Boiling point
4. Sublimation point
5. Unsaturated solution
π = CRT
y = x (m)
m = RT
310 R = RT
∴ T = 310 K
= 37º C

No. of moles of carbon present in 6 g of C-12 =
Mass / Molar mass
=6/12 = 0.5 moles = 0.5 × 6.022 × 1023
carbon atoms. No. of moles in 8 g of methane = 8 / 16 = 0.5 moles
=0.5 × 6.022 × 1023 carbon atoms.
=2 × 0.25 × 6.022 × 1023 carbon atoms.