Slaked lime Ca(OH)2
The suspension is called milk of lime and the clear
solution is called lime water.

Kf = 2.5 × 102
KC = 50
Kr = ?
Kc = Kf/Kr
50 = 2.5 x 102/ Kr
Kr = 5
Given :
ΔHC (CH4)= – 890 kJ
mol–1
ΔHC (C3H8)=
– 2220 kJ mol–1

SeF4, XeO2F2 - Sp3d
hybridisation,
First option T-shaped, one line pair on central atom.
areNo, of moles of oxygen=8 g/32 g
=0.25 moles of oxygen
No. of moles of sulphur dioxide=8 g / 64 g
=0.125 moles of sulphur dioxide
Ratio between the no. of molecules=0.25: 0.125
=2:1
