If the rth term in the expansion of contains then r =



Here, if we directly put x= 0, f(0) = 0 * sin (1/0) = 0.
At L.H.L, put x=0-h ,f(0-h) = = 0.
At R.H.L, put x = 0+h , , f(0+h) = = 0.
Hence, L.H.L = f(0) = R.H.L.
f(x) is continuous at x=0.
Terms of given sequence can be written as
so the required term is 33/32
here
hence r = 0, therefore there is no linear correlation.
