Q8.In the figure, assume that the forward voltage drops of the PN diode D1 and
Schottky diode D2 are 0 7. V and 0 3. V, respectively. If ON denotes conducting
state of the diode and OFF denotes non-conducting state of the diode, then in
the circuit,
Answer : Option DExplaination / Solution:
Alternatively, we can solve the problem by considering the current through two
diodes. Here, the correct case is only considered.
Case : Diode D1 is OFF, D2 is ON. For this case. The equivalent circuit is
From the circuit, we have
I1 = 0
I2 = 10 - 2.3/1.02
= 9.7/1.02
= 9.5 mA
Since, the current I2 is positive, So our assumption is correct.