


First we will fix one person from the 6 boys then 5 others can be arranged in 5! ways=120 ways
Now there are 6 places left in which 2 brothers can sit,so they can choose any 2 places from the 6 places in 6C2 ways=15 ways
Also 2 brothers can arrange themselves in 2! ways
So th ways in which the two brothers can be seated=15*2=30
Hence total ways in which all can be seated =120*30=3600
is
is given by: 


