


Comparing (i) and (iii) ,we get h=
Comparing (ii) and (iii) we get k=
putting value of h and k in (iii) we get



Total no. of outcomes = 6={2,2,2,6,6,6}
p(getting a six)=3/6=1/2
Given that there are 20 stations in the network .
Hence from each station 19 different tickets are possible
Therefore from 20 stations the number of different tickets possible=19 X 20=380
