Mathematics - Online Test

Q1.
Choose the correct expression for f(x) given in the graph.
Answer : Option C
Explaination / Solution:
No Explaination.


Q2. Four distinct points  and (0, 0) lie on a circle for
Answer : Option B
Explaination / Solution:

Because equation of circle will be x+ y- x - y =0 which is a quadratic equation and by putting the given fourth point we will get two different values of lemda.
Proof: let equation of cirle be 
As (1,0) (0,1) and (0,0) lie on circle ,we get

Comparing (i) and (iii) ,we get h=

Comparing (ii) and (iii) we get k=

putting value of h and k in (iii) we get 

hence we get equation of circle as 
now putting in above circle ,we get
which is quadratic and will give 2 values of 


Q3. Differential coefficient of a function f (g (x)) w.r.t. the function g (x) is
Answer : Option C
Explaination / Solution:

dd(g(x))(f(g(x))=f(g(x))
Q4. he general solution of tan 3x = 1 is (n ∈ I)
Answer : Option A
Explaination / Solution:



Q5. If  is divisible by c , when n is odd but not when n is even , then the value of c is :
Answer : Option C
Explaination / Solution:

Since a+b will be a factor of an +bn.

Q6. A dice has 3 faces each bearing ‘ 2 ‘ and three faces each bearing ‘ 6 ‘. It is rolled once. The probability of showing up ‘a six ‘ is
Answer : Option D
Explaination / Solution:

Total no. of outcomes = 6={2,2,2,6,6,6}

p(getting a six)=3/6=1/2


Q7. The plane x + y = 0 is
Answer : Option D
Explaination / Solution:
No Explaination.


Q8. Adj.(KA) = ….
Answer : Option B
Explaination / Solution:

 Adj.A , where K is a scalar and A is a n x n matrix.

Q9. On a railway track, there are 20 stations. The number of tickets required in order that it may be possible to book a passenger from every station to every other is
Answer : Option C
Explaination / Solution:

Given that there are 20 stations in the network .

Hence from each station 19 different tickets are possible

Therefore   from 20 stations the number of  different tickets  possible=19 X 20=380


Q10. Equation of a plane passing through three non collinear points (x1, y1, z1),(x2, y2, z2) and (x3, y3, z3) is
Answer : Option D
Explaination / Solution:

In cartesian co – ordinate system : Equation of a plane passing through three non collinear points (x1, y1, z1),(x2, y2, z2) and (x3, y3, z3) is given by :