Objective function is Z = 3x + 2 y ……………………(1).
The given constraints are : x + 2y ≤ 10, 3x + y ≤ 15, x, y ≥ 0. The corner points obtained by drawing the lines 3x+y=15 and x+2y=10 graphically are (0,0),(0,5), (5,0) and (4,3).
Corner points | Z = 3x + 2y |
O(0 ,0 ) | 0 |
A(5,0) | 15 |
B(0,5) | 10 |
C(4,3) | 18……………………..(Max.) |
Here , Z = 18 is maximum at ( 4, 3 )

R is a relation from { 11, 12, 13} to {8, 10, 12} defined by y = x – 3. The relation =
is equal to
The equation of the line perpendicular to the given line is x - y + k = 0
Since it passes through the origin,
0 - 0 + k = 0
Therefore k = 0
Hence the equation of the line is x - y = 0
On solving these two equations we get x = 1 and y = 1
The point of intersection of these two lines is (1,1)
Hence the coordinates of the foot of the perpendicular is (1,1)

definition of
Hence F


are collinear vectors , because are parallel in direction and same magnitude.