Mathematics - Online Test

Q1. The conditional probability of an event E, given the occurrence of the event F lies between
Answer : Option C
Explaination / Solution:

As the probability of any event always lies between 0 and 1. Therefore , 0 ≤ P (E|F) ≤ 1.

Q2. he value of is
Answer : Option B
Explaination / Solution:


Q3. The inequality  is true for :
Answer : Option B
Explaination / Solution:

When n = 1  we get , and when n = 2 we get ,. when n = 3 , which are inavlid inequations. Only when n = 4 we get , which is valid.

Q4. The function f (x) = [x] is
Answer : Option D
Explaination / Solution:

Case 1 Let c be a real number which is not equal to any integer. for all real numbers close to c the value of the function is equal to [c]; i.e., . Also and hence the function is continuous at all real numbers not equal to integers.

Case 2 Let c be an integer. Then we can find a sufficiently small real number  such that 

This, in terms of limits mean that 

Since these limits cannot be equal to each other for any c, the function is discontinuous at every integral point.


Q5. The number of points on X-axis which are at a distance c units (c 3) from ( 2, 3) is
Answer : Option B
Explaination / Solution:

the shortest distance from x-axis to the point is 3.

Q6. General solution of a given differential equation
Answer : Option C
Explaination / Solution:

The general solution of differential equation contains arbitrary constants equal to the order of differential equaition.

Q7. Shortest distance between is
Answer : Option A
Explaination / Solution:

Shortest distance between 
is given by :


Q8.

In a triangle ABC, a = 2b and  then angle A is


Answer : Option D
Explaination / Solution:



Q9. The number of different ways in which a man can invite one or more of his 6 friends to dinner is?
Answer : Option B
Explaination / Solution:

He can invite any one  friend in 6C1 ways= 6 ways:

He can invite any two friends in 6C2 ways = 15 ways

He can invite any three friends in 6C3 ways =20 ways

He can invite any 4 friends in 6C4ways = 15 ways

He can invite any 5 friends in 6C5 ways = 6 ways

He can invite  all the 6 friends in 6C6 ways= 1 way.

Since any one of these could happen total possibilities are, 6+15+20+15+6+1 = 63.


Q10. The lines having drs as a1a2+b1b2+c1c2=0 are
Answer : Option C
Explaination / Solution:


Hence lines are perpendicular