Mathematics - Online Test
. Consider the set ܵ of all vectors 
such that a2 + b2 = 1 where 
Then ܵ is
Given xyz=30
We have the possible values of x ,y,z are the following triads
1,1,30
1,2,15
1,3,10
1,5,6
2,3,5
First one can have 3!/2! = 3 ways and the remaining four triads can have 3! combinations
Hence total combinations = 3 + 4*3! = 27
The points of the complex plane given by the condition arg. ( z ) = ( 2n + 1 ) , n I lie on
Let number of kgs. of fertilizer F1 = x
And number of kgs. of fertilizer F2 = y
Therefore , the above L.P.P. is given as :
Minimise , Z = 6x +5y , subject to the constraints : 10/100 x + 5/100y ≥ 14 and 6/100x + 10/100y ≥ 14, i.e. 2 x + y ≥ 280 and 3x + 5y ≥ 700, x,y ≥ 0.,
Corner points | Z =6x +5 y |
A ( 0 , 280 ) | 1400 |
D(700/3,0 ) | 1400 |
B(100,80) | 1000………….(Min.) |
Corner points Z =6x +5 y A ( 0 , 280 ) 1400 D(700/3,0 ) 1400 B(100,80) 1000………….(Min.) Here Z = 1000 is minimum.
i.e. 100 kg of fertilizer F1 and 80 kg of fertilizer F2; Minimum cost = Rs 1000.
