

Only a null matrix can be symmetric as well as skew symmetric.
In Symmetric Matrix AT =A,
Skew Symmetric Matrix AT = -A,
Given that the matrix is satisfying both the properties therefore Equating the RHS we get A= -A i.e 2A=0 .
Therefore A=0,which is a null matrix.





expanding along R3



Since the limit is in the form of 0/0. By applying L'hospital first time we get,
Again using L'Hospital;
Again using L'Hospital we get