


If the coefficients of 2nd ,3rd and 4th terms in the expansion of are in A.P. then

N is set of natural number,so
x = 1/y
when y=1 then x=1
so
1 Q

Let number of pedestal lamps manufactured = x
And number of wooden shades manufactured = y
Therefore , the above L.P.P. is given as :
Maximise , Z = 5x +3y , subject to the constraints : 2x +y ≤ 12 and. 3x +2y ≤ 20 , x, y ≥ 0.
Corner points | Z =5x +3 y |
O( 0 , 0 ) | 0 |
D(6,0 ) | 30 |
A(0,10) | 30 |
B(4,4) | 32…………………(Max.) |
Here Z = 32 is maximum.
i.e 30 packages of screws A and 20 packages of screws B; Maximum profit = Rs 410.
i.e. 4 Pedestal lamps and 4 wooden shades; Maximum profit = Rs 32 .


