Given, (KH)A = x
(KH)B = y
xA/xB = 0.2
(xA/xB)in solution = ?
PA = x (xA) in solution –
(1)
PB = y (xB) in solution –
(2)
(xA/xB)in solution = (PB/PA)
. (x/y) = (xB/xA) . (x/y) = (1/0.2) . (x/y) = 5x/y
Tb – 100 = 1.06
Tb = 100 + 1.06
= 101.06 ≈ 101o C
0.1 × 3 ion [Ba2+,
2NO3–]
= 0.1 × 3 ion [2 Na+,
SO4–]
(π1)non electrolyte = (π2)glucose
C1RT = C2RT
[CH2O
=> 12+2+16=30]
W1/M1 = W1/M2
6 / n(30) = 0.025
n = 8
∴ molecular
formula = C8H16O8
Normality of H2SO4 = (no.of replacable
H+)×M
= 2 × 1.25
= 2.5 N
∆P / Pº =
Xsugar
3.5 × 10–3 = Xsugar
Xsugar + XH2o = 1
XH2o = 1 –
0.0035 = 0.9965