No. of moles of a gas that occupies a volume of
612.5 mL at room temperature and pressure (25 0 C and 1 atm
pressure)
=612.5 × 10-3 L / 24.5 Lmol-1
=0.025 moles
We know that,
Molar mass
=Mass / no. of moles
=1.1 g
/0.025 mol = 44 g mol-1
No. of moles of carbon present in 6 g of C-12 =
Mass / Molar mass
=6/12 = 0.5 moles = 0.5 × 6.022 × 1023
carbon atoms. No. of moles in 8 g of methane = 8 / 16 = 0.5 moles
=0.5 × 6.022 × 1023 carbon atoms.
=2 × 0.25 × 6.022 × 1023 carbon atoms.