Q1.Two parallel plate capacitors of capacitances C and 2C are connected in parallel and charged to a potential difference V by a battery. The battery is then disconnected and the space between the plates of capacitor C is completely filled with a material of dielectric constant K = 3. The potential difference across the capacitors now becomes
Answer : Option DExplaination / Solution: The charges on the capacitors after being charged to a potential V areQ1=CV;Q2=2CV.After being filled with a material of dielectric K=3 the capacitor which initially had a capacitance C has now the capacitance KC=3C. The common potential
Q2.A disk of radius a/4 having a uniformly distributed charge 6C is placed in the x-y plane with its centre at (−a/2, 0, 0). A rod of length a carrying a uniformly distributed charge 8C is placed on the x-axis from x = a/4 to x = 5a/4. Two point charges −7C and 3C are placed at (a/4, −a/4, 0) and (−3a/4, 3a/4, 0), respectively. Consider a cubical surface formed by six surfaces x=±a/2,y=±a/2,z=±a/2. The electric flux through this cubical surface is
Answer : Option CExplaination / Solution: Electric flux through a surface is given by ϕ=q∈0 Where q= net charge enclosed inside the surface Since half the disc lies inside the surface and one fourth of rod lies inside the surface, point charge −7Clies inside the surface and point charge 3C lies outside the surface So the net charge enclosed by the surface is=6C2−8C4−7C+0=−2C So ϕ=−2C∈0
Q4.Under the influence of the coulomb field of charge +Q, a charge −q is moving around it in an elliptical orbit. Find out the correct statement(s).
Answer : Option AExplaination / Solution:
Since the charge –q is moving in elliptical orbit so to make its motion stable the total angular momentum of the charge is constant since it experience a centripetal force from the charge +Q so it follow the motion as the motion of earth around sun.
Q5.Three capacitors, each of capacitance C = 3 mF, are connected as shown in the figure. The equivalent capacitance between points P and S is
Answer : Option AExplaination / Solution: If P is at positive potential, then Q is at negative potential and R is at positive potential. The system therefore reduces to 3 capacitors in parallel. C= 9μF
Q6.Consider a system of three charges q3,q3and−2q3placed at points A, B and C, respectively, as shown in the figure. Take O to be the centre of the circle of radius R and angle CAB = 60∘
Answer : Option CExplaination / Solution: The electric field due to charges at A and B are equal and opposite, So at O the electric field is due to C only, which has a magnitude E=2q12π0R2=q6π0R2The potential energy of the system is not zero Force between B and C F=q32q34π0(2RSin600)2=q254π0R2
Q7.An oil drop of 12 excess electrons is held stationary under a constant electric field of 2.55×104in Millikan’s oil drop experiment. The density of the oil is 1.26 g cm-3. Estimate the radius of the drop. (g = 9.81 m s−2; e = 1.60 × 10-19 C).
Answer : Option DExplaination / Solution: Density of oil, ρ = 1.26 gm/cm3 = 1.26 × 103 kg/m3 Acceleration due to gravity, g = 9.81 m s−2Charge on an electron, e = 1.6 × 10−19 C Radius of the oil drop = r Force (F) due to electric field E is equal to the weight of the oil drop (W) F = W Eq = mg Ene=mg Where,q = Net charge on the oil drop = ne m = Mass of the oil drop= Volume of the oil drop × Density of oil So Ene=ρ43πr32.55×104(12×1.6×10−19)= 1.26X103 × 43πr3So r = 9.82 × 10−4 mm Therefore, the radius of the oil drop is 9.82 × 10−4mm.
Q8.A parallel plate air filled capacitor shown in the Fig. (a) has a capacitance of 2 μF. When it is half filled with a dielectric of dielectric constant k = 3 as shown in Fig. (b), its capacitance becomes
Answer : Option DExplaination / Solution: The capacitance of the first capacitorC=ε0Ad=2μFThe second capacitor is considered to be made of two capacitors C1( air filled) and C2( dielectric) connected in series. The equivalent capacitance
Q9.A point charge q = -8.0 nC is located at the origin. Magnitude of the electric field vector at the field point x = 0.949m y = -1.643m is
Answer : Option CExplaination / Solution: Given x= 0.949m and y= -1.643 m Sor=x2+y2−−−−−−√=(0.949)2+(1.643)2−−−−−−−−−−−−−−−√=1.89mE=q4π∈0r2=8×10−9×9×109(1.89)2=20.15N/C
Q10.A parallel plate air filled capacitor shown in Fig. (a) has a capacitance of 2 μF. When it is half filled with a dielectric of dielectric constant k= 3 as shown in Fig. (b), its capacitance becomes
Answer : Option BExplaination / Solution: The capacitance of the first capacitor C=ε0Ad=2μFThe second capacitor is considered to be made of two capacitors C1( air filled) and C2( dielectric) connected in parallel.
Total Question/Mark :
Scored Mark :
Mark for Correct Answer : 1
Mark for Wrong Answer : -0.5
Mark for Left Answer : 0