A uniformly charged thin spherical shell of radius R carries uniform surface charge density of σ per unit area. It is made of two hemispherical shells, held together by pressing them with force F(See figure). F is proportional to
Answer : Option CExplaination / Solution: Outward electric field at the surface of shell is E=σ2ε0 If Q is the charge on the shell and A is the area, than the outward pressure is P=QEA=σE=σ22∈0 Force=PX effective area of hemispherical shell=σ22∈0×πR2So F∝σ2∈0R2
Q3.64 water drops having equal charges combine to form one bigger drop. The capacitance of the bigger drop, as compared to that of smaller drop will be
Answer : Option DExplaination / Solution: Capacitance of the small drop of radius r Cs=4πε0rand that of the big drop of radius R is CB=4πε0RThe volume of 64 small drops = volume of 1 big drop43πR3=64×43πr3;R=4rThe ratioCBCs=4πε0R4πε0r=Rr=4;CB=4Cs
Q4.Two charges A = -2.50 μC and B = 6.0 μC are at a distance of 1 meter from each other. Distance from A at which the electric field is zero in meters is
Answer : Option BExplaination / Solution: x=dq2q1ñ1where x= distance of null point from small charge, d=distance between two charges, q2=bigger charge, q1=small charge, +1 for like charges and -1 for unlike chargesx=162.50ñ1=1.85m
Q6.A long, hollow conducting cylinder is kept coaxially inside another long, hollow conducting cylinder of larger radius. Both the cylinders are initially electrically neutral.
Answer : Option AExplaination / Solution: When the charge is given to inner cylinder than there is an electric field is produced between cylinders which is given byE=λ2πε0rand due to this a potential difference is developed between two cylinders.
Q7.Three condensers of capacity 2 μF , 4 μF and 8 μF respectively, are first connected in series and then connected in parallel. The ratio of the equivalent capacitance in the two cases will be
Q8.Consider a neutral conducting sphere. A positive point charge is placed outside the sphere. The net charge on the sphere is then,
Answer : Option AExplaination / Solution:
If a charge q is placed outside than the electric field lines incident on the conducting sphere , if some charge is developed due to thee lines than opposite surface becomes oppositely charge and the total charge becomes zero.
Q9.A capacitor of capacitance C = 2 μFis connected as shown in the figure. If the internal resistance of the cell is 0.5Ω, the charge on the capacitor plates is
Answer : Option CExplaination / Solution: At steady state no current flows through the capacitor. The total resistance in the circuit =2+0.5=2.5Ω. Current I=V/R=2.5/2.5=1A. since no current flows through the 10 Ω resistor, the potential drop across it =0. The potential drop across the 2 Ω resistor = potential across the capacitor= I×2=2V.Charge on the capacitor Q= CV=(2μF)×(2V)=4μC.
Q10.Positive and negative point charges of equal magnitude are kept at ( 0,0,a/2) and (0,0,-a/2) respectively. The work done by the electric field when another positive point charge is moved from (-a,0,0) to (0,a,0) is
Answer : Option AExplaination / Solution: +Q charge is moving on equatorial line of dipole as shown in figure, since on equatorial line V=0 So W=0
Total Question/Mark :
Scored Mark :
Mark for Correct Answer : 1
Mark for Wrong Answer : -0.5
Mark for Left Answer : 0