Physics | NEET Entrance Exam | Under Graduate Entrance Exams Online Objective Test

Under Graduate Entrance Exams NEET Entrance Exam # Physics Nuclei Prepare / Learn

Q1.

At a given time there are 25

%

undecayed nuclei in a sample. After 10 seconds number of undecayed nuclei reduces to 12.5

%

. Then mean life of the nuclei will be about

A. 12 sec

B. 10 sec

C. 22 sec

D. 15 sec

Answer : Option D
Explaination / Solution:
No Explaination.

Under Graduate Entrance Exams NEET Entrance Exam # Physics Thermal Properties of Matter Prepare / Learn

Q2.

A spray can containing a propellant gas at twice atmospheric pressure (202 kPa) and having a volume of 125 $c m^{3}$ is at 22 $^{\circ}$ C. It is then tossed into an open fire. When the temperature of the gas in the can reaches 195 $^{\circ}$ C, what is the pressure inside the can? Assume any change in the volume of the can is negligible.

290 kPa

300 kPa

C. 320 kPa

D. 260 kPa

Answer : Option C
Explaination / Solution:

P∝TP1P2=T1T2P2=468×202295=320KPa

Under Graduate Entrance Exams NEET Entrance Exam # Physics Units and Measurements Prepare / Learn

Q3.

The unit of length convenient on the atomic scale is known as an angstrom and is denoted by $\overset{0}{A} : 1 \overset{0}{A} = 1 0^{- 10}$ m. The size of a hydrogen atom is about $0. 5 \overset{0}{A}$ . What is the total atomic volume in $m^{3}$ of a mole of hydrogen atoms ?

A. ≈3×10−7m3

B. ≅3.2×10−6m3

C. ≅3.3×10−7m3

≅ 2.9 \times 10^{- 6} m^{3}

≅ 2.9 \times 10^{- 6} m^{3}

Answer : Option A
Explaination / Solution:

Radius of hydrogen atom, r = 0.5 Å = 0.5 × 10-10 m
Volume of hydrogen atom = (4/3) π r3
= (4/3) × (22/7) × (0.5 × 10-10)3
= 0.524 × 10-30 m3
1 mole of hydrogen contains 6.023 × 1023 hydrogen atoms.
∴ Volume of 1 mole of hydrogen atoms = 6.023 × 1023 × 0.524 × 10–30
= 3.16 × 10–7 m3

$\approx 3 \times 10^{- 7} m^{3}$

Under Graduate Entrance Exams NEET Entrance Exam # Physics Oscillations Prepare / Learn

Q4. A cylinder floats vertically in a tank full of water. The period of oscillation of the cylinder when depressed and released is dependent on

A. Density of the liquid

B. The mass of the cylinder

C. Length of cylinder immersed in the liquid at equilibrium

D. The area of cross section of the cylinder

Answer : Option D
Explaination / Solution:
No Explaination.

Under Graduate Entrance Exams NEET Entrance Exam # Physics Magnetism and Matter Prepare / Learn

Q5. A closely wound solenoid of 2000 turns and area of cross-section

1.6 \times 1 0^{- 4} m^{2}

, carrying a current of 4.0 A, is suspended through its centre allowing it to turn in a horizontal plane. What is the magnetic moment associated with the solenoid?

A. 1.28Am2

B. 1.08Am2

C. 1.38Am2

D. 1.18Am2

Answer : Option A
Explaination / Solution:
No Explaination.

Under Graduate Entrance Exams NEET Entrance Exam # Physics Wave Optics Prepare / Learn

Q6. In a Young’s double-slit experiment, the slits are separated by 0.28 mm and the screen is placed 1.4 m away. The distance between the central bright fringe and the fourth bright fringe is measured to be 1.2 cm. Determine the wavelength of light used in the experiment

A. 640 nm

B. 620 nm

C. 660 nm

D. 600 nm

Answer : Option D
Explaination / Solution:
No Explaination.

Under Graduate Entrance Exams NEET Entrance Exam # Physics Moving Charges and Magnetism Prepare / Learn

Q7. A wire of length L carrying current i is placed perpendicular to the magnetic induction B. The total force on the wire is

A. LB/i

B. iB/L

C. iL/B

D. iLB

Answer : Option D
Explaination / Solution:

Magnitude of the Force experienced by a current carrying conductor placed in a magnetic field is . If the angle between the directions of the current and the magnetic field is 90⁰, F=iLB

Under Graduate Entrance Exams NEET Entrance Exam # Physics Electronic Devices Prepare / Learn

Q8. A p- type semiconductor can be obtained by adding

A. antimony to pure germanium

B. phosphorus to pure germanium

C. gallium to pure silicon

D. arsenic to pure silicon

Answer : Option C
Explaination / Solution:

In P-type doping, boron or gallium is the dopant. Boron and gallium each have only three outer electrons. When mixed into the silicon lattice, they form "holes" in the lattice where a silicon electron has nothing to bond to. The absence of an electron creates the effect of a positive charge, hence the name P-type. Holes can conduct current. A hole happily accepts an electron from a neighbor, moving the hole over a space. P-type silicon is a good conductor.

Under Graduate Entrance Exams NEET Entrance Exam # Physics Motion in A Straight Line Prepare / Learn

Q9.

A stone thrown from the top of a building is given an initial velocity of 20.0 m/s straight upward. Determine the maximum height it travels in meters. g =9.8 m / $s e c^{2}$

A. 30.4

B. 15.4

C. 20.4

D. 25.4

Answer : Option C
Explaination / Solution:

Initial velocity u = 20.0 m/s

At maximum height stone ll be stopped,

So final velocity v = 0 m/s

Acceleration due to gravity a = g =

-9.8 m/s2 (-ve Because it is in opposite direction of motion)

Let maximum height = s

We know,

$v^{2} - u^{2} = 2 a s$

=> $0^{2} - (20)^{2} = 2 \times (- 9.8) s$

$=> - 400 = - 19.6 s$

$=> s = \frac{- 400}{- 19.6} = 20.4 m$

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