Average KE depends only on temperature
A = Surface area of the box = 6s2 = 6 × (0.3)2 = 0.54 m3
Time gap, t = 6 h = 6 × 60 × 60 s
But Q = m'L
∴ m' = Q/L
= 104976/(335 × 103) = 0.313 kg
Mass of ice left = 4 – 0.3 = 3.7 kg
Hence, the amount of ice remaining after 6 h is 3.7 kg.