Physics | NEET Entrance Exam | Under Graduate Entrance Exams Online Objective Test

Under Graduate Entrance Exams NEET Entrance Exam # Physics Motion in A Straight Line Prepare / Learn

Q1. A stone thrown from the top of a building is given an initial velocity of 20.0 m/s straight upward. Determine the time in seconds at which the stone reaches its maximum height. g =9.8 m /

s e c^{2}

A. 2.8

B. 1.67

C. 2.7

D. 2.04

Answer : Option D
Explaination / Solution:

Initial velocity u = 20.0 m/s

At maximum height it ll stop

So final velocity v = 0 m/s

Acceleration due to gravity g = 9.8 m/s2

Time taken to reach maximum height = t

We know

v = u + at

=> $0 = 20 + (- 9.8) t$

$=> t = \frac{- 20}{- 9.8} = 2.04 s$ $=> t = \frac{- 20}{- 9.8} = 2.04 s$ [g is taken negative because it is in opposite direction of motion.]

Under Graduate Entrance Exams NEET Entrance Exam # Physics Waves Prepare / Learn

Q2. A tuning fork produces 4 beats/sec. with 50 cm and 40 cm of a stretched wire, of a sonometer. The frequency of fork is

A. 50 Hz

B. 36 Hz

C. 90 Hz

D. 110 Hz

Answer : Option B
Explaination / Solution:
No Explaination.

Under Graduate Entrance Exams NEET Entrance Exam # Physics Electromagnetic Waves Prepare / Learn

Q3. Use the formula E = hv (for energy of a quantum of radiation: photon) and obtain the photon energy in units of eV for for λ = 1 m

A. 1.24

\times 1 0^{- 6} e V

B. 1.44

\times 1 0^{- 6} e V

C. 1.54

\times 1 0^{- 6} e V

D. 1.34

\times 1 0^{- 6} e V

Answer : Option A
Explaination / Solution:
No Explaination.

Under Graduate Entrance Exams NEET Entrance Exam # Physics Electromagnetic Induction Prepare / Learn

Q4. Current in a circuit falls from 5.0 A to 0.0 A in 0.1 s. If an average emf of 200 V induced, estimate of the self-inductance of the circuit is

A. 3H

B. 5H

C. 2H

D. 4H .

Answer : Option D
Explaination / Solution:

L=−edi/dt=−200−5/0.1=4H

Under Graduate Entrance Exams NEET Entrance Exam # Physics Dual Nature of Radiation and Matter Prepare / Learn

Q5.

If an electron is accelerated by 8.8

\times 1 0^{14} m / s^{2}

then electric field required for acceleration is (given specific charge of the electron = 1.76

\times 1 0^{11} C k g^{- 1}

)

A. 54 V

c m^{- 1}

B. 50 V

c m^{- 1}

C. 56 V

c m^{- 1}

D. 52 V

c m^{- 1}

Answer : Option B
Explaination / Solution:

a=8.8×1014m/s2em=1.76×1011CKg−1a=Fm=eEm=(em)E8.8×1014=1.76×1011×EE=8.8×10141.76×1011=5000Vm−1=50Vcm−1

Under Graduate Entrance Exams NEET Entrance Exam # Physics Communication Systems Prepare / Learn

Q6. Ground wave propagation is used for

A. High frequency greater than 10GHz

B. Low frequency greater than 500 MHz and less than 1GHz

C. VLF few MHz

D. High frequency greater than 1GHz

Answer : Option C
Explaination / Solution:
No Explaination.

Under Graduate Entrance Exams NEET Entrance Exam # Physics Motion in A Plane Prepare / Learn

Q7. An aircraft is flying at a height of 3400 m above the ground. If the angle subtended at a ground observation point by the aircraft positions 10.0 s apart is 30

^{\circ}

, what is the speed of the aircraft?

A. 172 m/s

B. 192 m/s

C. 193 m/s

D. 182 m/s

Answer : Option D
Explaination / Solution:

The positions of the observer and the aircraft are shown in the given figure.

Height of the aircraft from ground, OR = 3400 m
Angle subtended between the positions, ∠POQ = 30°
Time = 10 s
In ΔPRO:
tan 15° = $\frac{P R}{O R}$
PR = OR tan 15°
= $3400 \times t a n 15 °$

ΔPRO is similar to ΔRQO.
∴PR = RQ
PQ = PR + RQ
= 2PR = 2 × 3400 tan 15°
= 6800 × 0.268 = 1822.4 m
∴ Speed of the aircraft = $\frac{1822.4}{10}$

= 182.24 m/s $\approx 182$ m/s

Under Graduate Entrance Exams NEET Entrance Exam # Physics Electric Charges and Fields Prepare / Learn

Q8. An electric dipole with dipole moment

4 \times 1 0^{- 9} C

m is aligned at

3 0^{\circ}

with the direction of a uniform electric field of magnitude

5 \times 1 0^{4} N C - 1

.Calculate the magnitude of the torque acting on the dipole.

A. 1.0×10−4Nm

B. 1.5×10−8Nm

C. 3.5×10−4Cm

D. 3.5×10−4Cm

Answer : Option A
Explaination / Solution:

τ=pESinθ=4×10−9×5×104Sin300=1×10−4Nm

Under Graduate Entrance Exams NEET Entrance Exam # Physics Mechanical Properties of Solids Prepare / Learn

Q9.

In constructing a large mobile, an artist hangs an aluminum sphere of mass 6.0 kg from a vertical steel wire 0.50 m long and 2.5

\times

1 0^{- 3}

c m^{2}

in cross-sectional area. On the bottom of the sphere he attaches a similar steel wire, from which he hangs a brass cube of mass 10.0 kg. Compute the tensile strain.

A. 3.3

\times

1 0^{- 3}

upper, 2.4

\times

1 0^{- 3}

lower

B. 3.4

\times

1 0^{- 3}

upper, 2.5

\times

1 0^{- 3}

lower

C. 3.2

\times

1 0^{- 3}

upper, 2.3

\times

1 0^{- 3}

lower

D. 3.1

\times

1 0^{- 3}

upper, 2.0

\times

1 0^{- 3}

lower

Answer : Option D
Explaination / Solution:
No Explaination.

Under Graduate Entrance Exams NEET Entrance Exam # Physics Thermodynamics Prepare / Learn

Q10.

A 1.0-mol sample of an ideal gas is kept at 0.0 $^{\circ}$ C during an expansion from 3.0 L to 10.0 L. How much energy transfer by heat occurs with the surroundings in this process?

A. 2.8

\times

1 0^{3}

B. 2.9

\times

1 0^{3}

C. 2.7

\times

1 0^{3}

D. 3.0

\times

1 0^{3}

Answer : Option C
Explaination / Solution:

in isothermal process $Δ U = 0$

hence $Δ Q = W$

$Q = n R T \log_{e} \frac{V_{f}}{V_{i}}$

$Q = 1 \times 8.31 \times 273 \times 2.303 \log_{10} \frac{10}{3} = 2.7 \times 10^{3} J$

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