TN 11TH CHEMISTRY - Online Test

mass of methane

= mass of oxygen = a

number of moles of methane = a/16

number of moles of Oxygen = a/32

mole fraction of Oxygen =

=[a/32] / [{a/16} + {a/32{ ]

= [a/32] / [3a/32]

=1/32

Partial pressure of oxygen

= mole fraction Total Pressure

=1/3 P

K_H = 8 × 10⁴

(x_N2)_{in air} = 0.5

Total pressure = 4 atm

pressure Partial pressure of nitrogen = mole fraction × total pressure = 0.5 × 4 = 2

2-butynal

no. of σ bonds = 8[4C-H;,3C-C;1C-O]

no. of π bonds = 3[2C-C; 1C-O]

ratio=8/3

Weight of the water drop  =0.018 g

No. of moles of water in the drop=Mass of water / molar mass

=  0.018 / 18 = 10^-3 mole

No of water molecules present in 1 mole of water= 6.022 x 10²³

No. water molecules in one drop of water (10^-3 mole)= 6.022 x 10²³x 10^-3

=6.022 x 10²⁰

n = 6 to n=5

E₆ = -13.6 / 6² ;

E₅ = - 13.6 / 5²

E₆ - E₅ = (-13.6 /6²) - (-13.6/5²)

= 0.166 eV atom^-1

E₅ - E₄ = (-13.6 /5²) - (-13.6/4²)

= 0.306 eV atom^-1