A truck starts from rest and accelerates uniformly at 2.0 m . At t = 10 s, a stone is dropped by a person standing on the top of the truck (6 m high from the ground). What is the magnitude of velocity (in m ) of the stone at t = 11s? (Neglect air resistance.)
During first 10 , the horizontal component of the velocity is vx = u + at = 0+2x10 = 20 m/s
From 10 to 11 s, the vertical component of the velocity is vy=u + gt = 0 + 10x1 = 10m/s
Relative velocity is,