Physics - Online Test

Q1. When a mass is rotating in a plane about a fixed point, its angular momentum is directed along
Answer : Option B
Explaination / Solution:

cular to both 

  and   that is along the axis of rotation according to right hand screw rule.


Q2. A man in a lift is holding a can filled with water but having a hole in its bottom. When will the drainage of water be maximum?
Answer : Option B
Explaination / Solution:
No Explaination.


Q3.

A tank used for filling helium balloons has a volume of 0.300  and contains 2.00 mol of helium gas at 20.0. Assuming that the helium behaves like an ideal gas, What is the average kinetic energy per molecule?


Answer : Option B
Explaination / Solution:

E=32kT=32×1.38×1023×293=6.07×1021J
Q4. The magnifying power of the telescope can be increased by
Answer : Option B
Explaination / Solution:
No Explaination.


Q5. A radioactive substance has a half life of four months. Three fourths of the substance will decay in
Answer : Option B
Explaination / Solution:
No Explaination.


Q6. Find the wrong statement about specific heat of a material
Answer : Option A
Explaination / Solution:

extensive properties (i.e. mass) are dependent upon the amound of a substance, while intensive properties (i.e. density) are independent of quantity.

Q7. Approximately How many km is 3 m ?
Answer : Option B
Explaination / Solution:

1 km h​​​​​​-2 = 

=> 

=> 

=> 


Q8. A 200 ohm resistor is connected in series with a 5μF capacitor. The voltage across the resistor is VR = (1.20 V) cos(2500 rad/s)t . Capacitive reactance is
Answer : Option A
Explaination / Solution:

VR = (1.20 V) cos(2500 rad/s)t

ω=2500rad/s

C=5μF=5×106F

Capacitive reactance

XC=1ωC=12500×5×106=80Ω


Q9. A milliammeter of range 10 mA and resistance 9 ohms is joined in a circuit as shown. The device gives full-scale deflection for current I when A and B are used as its terminals, i.e., current enters at A and leaves at B (C is left isolated). The value of total current I is

Answer : Option D
Explaination / Solution:

Thee above circuit can be redrawn as:

Total resistance in the arm EF ( milliammeter and the 0.9Ω resistor)= 9+0.9=9.9Ω.

Since the milliammeter gives full scale deflection when A and B are used as its terminals, the current in the arm EF is 10 mA. The potential difference across the arm is 

VEF = Ig* R = 10(10^ - 3) * 9.9 = 0.099V.

The potential difference across AB= potential diff across the 0.1Ω resistor= VEF = 0.099 V.

The current through the 0.1Ω resistor


The total current I is the sum of I0.1 and Ig 

= Ig + I0.1 = 0.01 + 0.99 = 1A.


Q10. A simple spring has length l and force constant K. It is cut into two springs of lengths  and  such that  =n. (where n is an integer), the force constant of the spring of length  is
Answer : Option C
Explaination / Solution:
No Explaination.