
Let,
T =tension in the string,
a= acceleration in the direction of force F.

m1=10 kg and m2= 20 kg
Therefore,common acceleration
Now the tension T in the string is
A trolley of mass 200 kg moves with a uniform speed of 36 km/h on a frictionless track. A child of mass 20 kg runs on the trolley from one end to the other (10 m away) with a speed of 4 m relative to the trolley in a direction opposite to the its motion, and jumps out of the trolley. What is the final speed of the trolley?
Mass of troly M = 200Kg
mass of child m = 20Kg
speed of trolley v = 36Km/hr=36 x 5/18 = 10m/s
Let v' be the final velocity of the trolley with respect to the ground.
Final velocity of the boy with respect to the ground =
from conservation of linear momentum