Physics | NEET Entrance Exam | Under Graduate Entrance Exams Online Objective Test

Under Graduate Entrance Exams NEET Entrance Exam # Physics Motion in A Plane Prepare / Learn

Q1. The reason why cyclists bank when taking a sharp turn is

A. to supply the sidewise (centripetal) acceleration required to make the direction change

B. cyclists enjoy turning to one side and so bank

C. to supply the acceleration required to move fast

D. to decelerate at the turns as turns are dangerous

Answer : Option A
Explaination / Solution:

In order to take a safe turn, the cyclist has to bend a little from his vertical position. In this case, a component of the reaction provides the required centripetal force.

If q is angle made by the cyclist with the vertical then

$N c o s θ = m g . . . . (1)$

$N s i n θ = \frac{m v^{2}}{r} . . . . . (2)$

Dividing (2) by (1), we get

$\tan θ = \frac{v^{2}}{r g}$

=> $θ = t a n^{- 1} (\frac{v^{2}}{r g})$

In actual practice, the value of q is slightly less because the force of friction also contributes towards the centripetal force.

Under Graduate Entrance Exams NEET Entrance Exam # Physics Electric Charges and Fields Prepare / Learn

Q2. A point charge causes an electric flux of

- 1 .0 \times 1 0^{3} N m^{2} / C

to pass through a spherical Gaussian surface of 10.0 cm radius centred on the charge. (a) If the radius of the Gaussian surface were doubled, how much flux would pass through the surface? (b) What is the value of the point charge?

A. −103Nm2/C,−8.8nC

B. −103Nm2/C,−6.8nC

C. 103Nm2/C,−8.8nC

D. 103Nm2/C,−7.8nC

Answer : Option A
Explaination / Solution:

(a) Electric flux is given by

ϕ = \frac{q}{\in_{0}}

since amount of charge not depends on size and shape so by making radius double the amount of charge remain same so electric flux remain same.

Under Graduate Entrance Exams NEET Entrance Exam # Physics Mechanical Properties of Solids Prepare / Learn

Q3. Four identical hollow cylindrical columns of mild steel support a big structure of mass 50,000 kg. The inner and outer radii of each column are 30 and 60 cm respectively. Assuming the load distribution to be uniform, calculate the compression strain of each column. . Take Young's modulus of steel as 20

\times

1 0^{10}

A. 2.9

\times

1 0^{- 6}

B. 3.1

\times

1 0^{- 6}

C. 2.8

\times

1 0^{- 6}

D. 3.0

\times

1 0^{- 6}

Answer : Option C
Explaination / Solution:
No Explaination.

Under Graduate Entrance Exams NEET Entrance Exam # Physics Thermodynamics Prepare / Learn

Q4. A water heater is operated by solar power. If the solar collector has an area of 6.00

m^{2}

and the power delivered by sunlight is 550 W/

m^{2}

, how long does it take to increase the temperature of 1.00

m^{3}

of water from 20.0

^{\circ}

C to 60.0

^{\circ}

A. 51.7 ks

B. 48.7 ks

C. 52.7 ks

D. 50.7 ks

Answer : Option D
Explaination / Solution:

$\begin{aligned} Q = m s Δ T \\ P = \frac{W}{t} = \frac{m s Δ T}{t} \end{aligned}$

$t = \frac{m s Δ T}{P} = \frac{1000 \times 4186 \times 40}{550 \times 6} = 50700 \sec = 50.7 K \sec$

Under Graduate Entrance Exams NEET Entrance Exam # Physics Laws of Motion Prepare / Learn

Q5. Figure shows the position-time graph of a particle of mass 4 kg. What is the impulse at t = 0 and t = 4 s ? (Consider one-dimensional motion only)

A. 2 kg m

s^{- 1}

at t=0 and -2 kg m

s^{- 1}

at t = 4 s

B. 5 kg m

s^{- 1}

at t=0 and -3 kg m

s^{- 1}

at t = 4 s

C. 4 kg m

s^{- 1}

at t=0 and -4 kg m

s^{- 1}

at t = 4 s

D. 3 kg m

s^{- 1}

at t=0 and -3 kg m

s^{- 1}

at t = 4 s

Answer : Option D
Explaination / Solution:

Initial velocity $u = 0$ , between t= 0s and t=4s, the particle has a constant velocity,

therefore slope of OA is $v = \frac{3}{4} m / s$

At t= 0,Impulse=Change in momentum

= $m (v - u) = 4 (\frac{3}{4} - 0) = 3 k g m / s$

At t= 4s, initial velocity is 3/4 m/s,

So, the Impulse = $m (v - u) = 4 (0 - \frac{3}{4}) = - 3 k g m / s$

Under Graduate Entrance Exams NEET Entrance Exam # Physics Current Electricity Prepare / Learn

Q6. In the figure, when an ideal voltmeter is connected across 4000 ohm resistance, it reads 30 volts. If the voltmeter is connected across 3000 ohms resistance. It will read

A. 35 volt

B. 22.5 volt

C. 20 volt

D. 40 volt

Answer : Option B
Explaination / Solution:

An ideal voltmeter does not draw any current. Therefore the resistances 4000 Ω and 3000 Ω are in series. The current in the circuit

$\begin{array}{l} I = \frac{V_{4000}}{4000} = \frac{30}{4000} A \end{array}$

The potential difference across the 3000 Ω resistor

Under Graduate Entrance Exams NEET Entrance Exam # Physics Work Energy and Power Prepare / Learn

Q7. A bolt of mass 0.3 kg falls from the ceiling of an elevator moving down with an uniform speed of 7 m/s. It hits the floor of the elevator (length of the elevator = 3 m) and does not rebound. What is the heat produced by the impact?

A. 8.42 J

B. 8.82 J

C. 8.11 J

D. 9.22 J

Answer : Option B
Explaination / Solution:

Whole of the potential energy of bolt converted in to heat energy heat produced by the impact = mgh =0.3×9.8×3=8.82J

$\begin{aligned} m g \sin 37^{\circ} - μ m g \cos 37^{\circ} = \frac{1}{2} k x^{2} \\ (1 \times 9.8 \times 0.6) - (μ \times 1 \times 9.8 \times 0.8) = \frac{1}{2} \times 100 \times 0.1 \\ 0.602 - 0.799 μ = 0.510 \\ μ = \frac{0.092}{0.799} = 0.115 \end{aligned}$

Under Graduate Entrance Exams NEET Entrance Exam # Physics Atoms Prepare / Learn

Q8. It is found experimentally that for small thickness t, the number of α-particles scattered at moderate angles is proportional to t. What clue does this linear dependence on t provide?

A. scattering is predominantly due to multiple collisions

B. scattering is predominantly due to deflecting fields being proportional to t

C. scattering is predominantly due to no collison

D. scattering is predominantly due to a single collision

Answer : Option D
Explaination / Solution:
No Explaination.

Under Graduate Entrance Exams NEET Entrance Exam # Physics Electrostatic Potential and Capacitance Prepare / Learn

Q9. The plates of a parallel plate capacitor are 10 cm apart and have area equal to 2m². If the charge on each plate is

8.85 \times 1 0^{- 10} C

, the electric field at a point

A. outside the plates will be zero

B. between the plates will change from point to point

C. between the plates will be

25 N C^{- 1}

D. between the plates will be zero

Answer : Option A
Explaination / Solution:

The electric field outside two large plates with opposite charge densities will be zero.

The electric field between the plates of the capacitor

and it is a constant electric field.

Under Graduate Entrance Exams NEET Entrance Exam # Physics Physical World Prepare / Learn

Q10. Weak Nuclear Force

A. is responsible for a common form of radioactivity called beta decay

B. is responsible for holding the electrons and the nucleus together

C. is responsible for holding the electrons of the nucleus together

D. is responsible for holding the constituents of the nucleus together

Answer : Option A
Explaination / Solution:

The weak nuclear force stops a neutron from decaying into a proton and an electron. When this happens, an electron leaves the atom. This is known as beta decay.

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