Physics - Online Test

Q1. If a magnet is suspended over a container of liquid air, it attracts droplets to its poles. The droplets contain only liquid oxygen and no nitrogen because
Answer : Option D
Explaination / Solution:
No Explaination.


Q2. A solid having uppermost energy – band partially filled with electrons is called
Answer : Option D
Explaination / Solution:
No Explaination.


Q3. With reference to the figure which shows a particle moving along a straight line , y axis represents the position and x axis represents time, if  = 18m, The average velocity at if  in m/s is

Answer : Option A
Explaination / Solution:

Average velocity can be defined as the displacement divided by the time.

Total displacement d = 18 m

Time taken t = 1 s

average velocity 


Q4. Two tuning forks of frequencies 250 Hz produce beats. If a maximum is produced just now, after how much time the minimum is produced at the same place
Answer : Option D
Explaination / Solution:
No Explaination.


Q5. The amplitude of the magnetic field part of a harmonic electromagnetic wave in vacuum is = 510 nT. Amplitude of the electric field part of the wave is
Answer : Option B
Explaination / Solution:
No Explaination.


Q6.

A circular coil of radius 8.0 cm and 20 turns is rotated about its vertical diameter with an angular speed of 50 rad  in a uniform horizontal magnetic field of magnitude  T. If the coil resistance is , maximum emf induced in the coil,maximum value of current in the coil and average power loss due to Joule heating are


Answer : Option C
Explaination / Solution:



average power loss due to joule heating 


Q7. If the wavelength of light incident on photo-electric cell be reduced from 4000 to3600,then what will be the change in the cut off potential. 
Answer : Option B
Explaination / Solution:
No Explaination.


Q8. To radiate signals with high efficiency, the antennas should have a size
Answer : Option A
Explaination / Solution:
No Explaination.


Q9. The position of a particle is given by  Find the velocity and acceleration of the particle.
Answer : Option A
Explaination / Solution:

Position vector  

We know velocity is given by


So 

Acceleration is given by 


So, 


Q10. Four point charges qA=2μC,qB=−5μC,qC=2μC,andqD=−5μC are located at the corners of a square ABCD of side 10 cm. Force on a charge of 1μC placed at the centre of the square is
Answer : Option C
Explaination / Solution:



EB-ED=0 and so the net electric field at centre=0 so force on charge 1µC=0