Electrical Engineering - Online Test
Q1. A network consisting of a finite number of linear resistor (R), inductor (L), and capacitor (C)
elements, connected all in series or all in parallel, is excited with a source of the form
The source has nonzero impedance. Which one of the following is a possible form of the
output measured across a resistor in the network?
Answer : Option A
Explaination / Solution:
The property of any LTI system or network is if the excitation contains „n‟ number of different
frequency then the response also contains exactly n number of different frequency term and the
output frequency and input frequency must be same however depending on components there
is a possible change in amplitude and phase but never the frequency.
⟶ If the source has 3 frequency terms as given 
then any voltage or any current of any element should have also 3 terms based on this option (B) and (D) are eliminated.
then any voltage or any current of any element should have also 3 terms based on this option (B) and (D) are eliminated.⟶ If we take option (C). It has 3 frequency term but it also suggest there is a phase change so ϕk but amplitude must be same as input as ak is present which may not be true always.
⟶ So option (A) is correct, as it suggest frequency term of output and inputs are same with
possible change in amplitude and phase, because we have (bk and ϕk ).
Q2. Identify the circuit below.
Answer : Option A
Explaination / Solution:
No Explaination.
Q3. The Bode plot of a transfer function G(s) h is shown in the figure below.
The gain (20 log ƖG(S)Ɩ) is 32 dB and -8 dB at 1 rad/s and 10 rad/s respectively The phase is negative for all ω Then G(S) is
Answer : Option B
Explaination / Solution:
From the given plot, we obtain the slope as
Q4. Given 
then the value of k is
then the value of k is
Answer : Option D
Explaination / Solution:
By final value theorem
Q5. The functionality implemented by the circuit below is
Answer : Option B
Explaination / Solution:
Decoder inputs will behaves as MUX select lines and when the output of decoder is high then only corresponding buffer will be enable and passed the inputs (P,Q,R,S) to the outpuut line, so it will work as 4-to-1 multiplexer.
Q6. In the circuit shown below, if the source voltage 
then the
Thevenin’s equivalent voltage in Volts as seen by the load resistance RL is
then the
Thevenin’s equivalent voltage in Volts as seen by the load resistance RL is
Answer : Option C
Explaination / Solution:
No Explaination.
Q7.
In a voltage-voltage feedback as shown below, which one of the following statements is TRUE if the gain k is increased?
Answer : Option A
Explaination / Solution:
The i/p voltage of the system is given as
Therefore, if k is increased then input voltage is also increased so, the input impedance increases. Now, we have
Since, Vin is independent of k when seen from output mode, the output voltage decreases with increase in k that leads to the decrease of output impedance. Thus, input impedance increases and output impedance decreases.
Q8. A fair coin is tossed 10 times. What is the probability that only the first two tosses will yield heads?
Answer : Option C
Explaination / Solution:
Number of elements in sample space is 210 Only one element "H,H,T,T,T,T,T,T,T,T, is event. Thus probability is 1/210
Q9. In an 8085 system, a PUSH operation requires more clock cycles than a POP operation. Which one of the following options is the correct reason for this?
Answer : Option C
Explaination / Solution:
In push operation 3 cycles involved: 6T+3T+3T = 127
POP operation 3 cycle involved: 4T+3T+3T = 107
So in the opcode fetch cycle 2T states are extra in case of push compared to POP and this is needed to decrement the SP.
Q10. The following arrangement consists of an ideal transformer and an attenuator
which attenuates by a factor of 0.8. An ac voltage VWXI = 100 V is applied
across WX to get an open circuit voltage VYZ1 across YZ. Next, an ac voltage VYZ2 = 100 V is applied across YZ to get an open circuit voltage VWX2 across
WX. Then, VYZI/VWX1, VWX2/VYZ2 are respectively.
Answer : Option C
Explaination / Solution:
