According to Henderson equation
pH = pKa + log ([salt]/[acid])
ie. - log [H+ ] = -
log Ka +log ([salt] / [acid])
-log[H+] = log ([salt]/ [acid]) ×
(1/Ka)
log (1/[H+]) = log ([salt]/ [acid]) × (1/Ka)
∴[H+] = Ka
{[acid] / [salt] }
Kh = Kw/Kb =
1×10-14 / 1.8×10-5
= 0.55×10-9
= 5.5×10-10